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软件设计师每日一练试题(2026/10/20)

2026年10月21日来源:信管网 作者:cnitpm

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软件设计师每日一练试题内容(2026/10/20)

  • 试题1

    Why is(1)fun? What delights may its practitioner espect his reward? First is the
    sheer joy of making things.As the child delights in his mud pie,so the adult enjoys
    building things,especially things of his own design.Secong is the pleasure of making
    things that are useful to other people.Third is the fascinanon of fashioning complex
    puzzle-like objects  of interlocking moving  parts and watching them  work in subtle
    eyeles,playing out the consequences of principies built in from the beginning.Fourth
    is the joy of always learning,which springs from the(2)nature of the task.In one way
    or    another    the    problem    is    ever    new,and    its    solver    learns
    something:sometimes(3),sometimes  theoretical,and  sometimes both.Finally,there  is
    the delight of working in such a tractable medium.The(4),like the poet,works only
    slightly removed from nure thought-stuff.Few media of ereation are so flexible,so easy
    to polish and rework,so readily capable of realizing grand conceptual structures.
    Yet the program(5),unlike the poet’s words,is real in the sense that it moves and
    works,producing  visible  outputs  separate  from  the  comstrct  itself.It  prints
    results,draws pictures,produces sounds,moves arms.Progamming then is fun because it
    gratifies creative longings built deep within us and delights sensibities we hav e in
    common with all men.
    (1)A、programming
    B、composing
    C、working
    D、writing
    (2)A、repeating
    B、basic
    C、non-repeating
    D、advance
    (3)A、semantic
    B、practical
    C、lexical
    D、syntactical
    (4)A、poet
    B、architect
    C、doctor
    D、programmer
    (5)A、construct
    B、code
    C、size
    D、scale

    查看答案

    试题参考答案:A、C、B、D、A

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/20

  • 试题2

    主域名服务器在接收到域名请求后,首先查询的是( )。
    A.本地hosts文件

    查看答案

    试题参考答案:C

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/20

  • 试题3

    在 UML 类图中,类与类之间存在依赖(Dependency)、关联(Association)、聚合(Aggregation)、组合(Composition)和继承(Inheritance)五种关系,其中,(1)关系表明类之间的相互联系最弱,(2)关系表明类之间的相互联系最强,聚合(Aggregation)的标准 UML 图形表示是(3)  。
    (3)
    (1)A、依赖
    B、聚合
    C、组合
    D、继承
    (2)A、依赖
    B、聚合
    C、组合
    D、继承
    (3)A. A

    查看答案

    试题参考答案:A、D、B

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/20

  • 试题4

    TCP使用的流量控制协议是( )。
    A.固定大小的滑动窗口协议

    查看答案

    试题参考答案:C

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/20

  • 试题5

    The project workbook is not so much a separate document as it is a structure imposed on the documents that the project will be producing anyway.
    All the documents of the project need to be part of this ( ). This includes objectives ,external specifications , interface specifications , technical standards , internal specifications and administrative memoranda(备忘录).
    Technical prose is almost immortal. If one examines the genealogy ( Ff ) of a customer manual for a piece of hardware or software , one can trace not only the ideas , but also many of the very sentences and paragraphs back to the first ( ) proposing the product or explaining the first design. For the technical writer, the paste-pot is as mighty as the pen.
    Since this is so, and since tomorrow's product-quality manuals will grow from today’s memos, it is very important to get the structure of the documentation right. The early design of the project (请作答此空) ensures that the documentation structure itself is crafted, not haphazard. Moreover, the establishment of a structure molds later writing into segments that fit into that structure.
    The second reason for the project workbook is control of the distribution of ( ). The problem is not to restrict information, but to ensure that relevant information gets to all the people who need it.
    The first step is to number all memoranda, so that ordered lists of titles are available and h worker can see if he has what he wants. The organization of the workbook goes well beyond this to establish a tree-structure of memoranda. The ( ) allows distribution lists to be maintained by subtree, if that is desirable.
    A.title

    查看答案

    试题参考答案:C

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/20

  • 试题6

    下列关于风险的叙述中,不正确的是( )。
    A.风险是可能发生的事件

    查看答案

    试题参考答案:B

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/20

  • 试题7

    AES是一种( )算法。
    A、公钥加密
    B、流密码
    C、分组加密
    D、消息摘要

    查看答案

    试题参考答案:C

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/20

  • 试题8

    某些设计模式会引入总是被用作参数的对象。例如(  )对象是个多态accept方法的参数。
    A.Visitor

    查看答案

    试题参考答案:A

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/20

  • 试题9

    在结构化分析中,用数据流图描述(1 )。当采用数据流图对一个图书馆管理系统进行分析时,(2 )是一个外部实体。
    (1)A.数据对象之间的关系,用于对数据建模

    查看答案

    试题参考答案:B、A

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/20

  • 试题10

    ( )是对稀疏矩阵进行压缩存储的方式。
    A.二维数组和双向链表

    查看答案

    试题参考答案:B

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/20

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