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软件设计师每日一练试题(2026/10/15)

2026年10月16日来源:信管网 作者:cnitpm

软件设计师当天每日一练试题地址:www.cnitpm.com/exam/ExamDay.aspx?t1=4

往期软件设计师每日一练试题汇总:www.cnitpm.com/class/27/e4_1.html

软件设计师每日一练试题(2026/10/15)在线测试:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/15

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软件设计师每日一练试题内容(2026/10/15)

  • 试题1

    程序员甲将其编写完成的软件程序发给同事乙并进行讨论,之后由于甲对该程序极不满意,因此甲决定放弃该程序,后来乙将该程序稍加修改并署自己名在某技术论坛发布。下列说法中,正确的是( )。
    A.乙对该程序进行了修改,因此乙享有该程序的软件著作权

    查看答案

    试题参考答案:D

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/15

  • 试题2

    The project workbook is not so much a separate document as it is a structure imposed on the documents that the project will be producing anyway.
    All the documents of the project need to be part of this (请作答此空). This includes objectives ,external specifications , interface specifications , technical standards , internal specifications and administrative memoranda(备忘录).
    Technical prose is almost immortal. If one examines the genealogy ( Ff ) of a customer manual for a piece of hardware or software , one can trace not only the ideas , but also many of the very sentences and paragraphs back to the first ( ) proposing the product or explaining the first design. For the technical writer, the paste-pot is as mighty as the pen.
    Since this is so, and since tomorrow's product-quality manuals will grow from today’s memos, it is very important to get the structure of the documentation right. The early design of the project ( ) ensures that the documentation structure itself is crafted, not haphazard. Moreover, the establishment of a structure molds later writing into segments that fit into that structure.
    The second reason for the project workbook is control of the distribution of ( ). The problem is not to restrict information, but to ensure that relevant information gets to all the people who need it.
    The first step is to number all memoranda, so that ordered lists of titles are available and h worker can see if he has what he wants. The organization of the workbook goes well beyond this to establish a tree-structure of memoranda. The ( ) allows distribution lists to be maintained by subtree, if that is desirable.
    A.structure

    查看答案

    试题参考答案:A

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/15

  • 试题3

    给定教师关系Teacher(T_no,T_name,Dept_name,Tel),其中属性T_no、T_name、Dept_name和Tel的含义分别为教师号、教师姓名、学院名和电话号码。用SQL创建一个“给定学院名求该学院的教师数”的函数如下:
    CreatefunctionDept_count(Dept_namevarchar(20))
    ( )
    begain
    ( )
    selectcount(*)intod_count
    fromTeacher
    whereTeacher.Dept_name=Dept_name
    retumd_count
    end
    (1)
    A.returnsinteger

    查看答案

    试题参考答案:A、D

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/15

  • 试题4

    以编译方式翻译C/C++源程序的过程中,类型检查在( )阶段处理。
    A.词法分析

    查看答案

    试题参考答案:B

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/15

  • 试题5

    无向图中一个顶点的度是指图中( )。
    A、通过该顶点的简单路径数
    B、通过该顶点的回路数
    C、与该顶点相邻接的顶点数
    D、与该顶点连通的顶点数

    查看答案

    试题参考答案:C

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/15

  • 试题6

    ( )不属于入侵检测技术。
    A.专家系统

    查看答案

    试题参考答案:D

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/15

  • 试题7

    将高级语言程序翻译为机器语言程序的过程中,常引入中间代码,其好处是( )
    A、有利于进行反编译处理
    B、有利于进行与机器无关的优化处理
    C、尽早发现语法错误
    D、可以简化语法和语义分析

    查看答案

    试题参考答案:B

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/15

  • 试题8

    (1)  限制了创建类的实例数量,而 (2)  将一个类的接口转换成客户希望的另外一个接口,使得原本由于接口不兼容而不能一起工作的那些类可以一起工作。
    (1)A、命令模式(Command)
    B、适配器模式(Adapter)
    C、策略模式(Strategy)
    D、单例模式(Singleton)
    (2)A、命令模式(Command)
    B、适配器模式(Adapter)
    C、策略模式(Strategy)
    D、单例模式(Singleton)

    查看答案

    试题参考答案:D、B

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/15

  • 试题9

    页式存储系统的逻辑地址是由页号和页内地址两部分组成。假定页面的大小为4K,地址变换过程如下图所示,图中逻辑地址用十进制表示。
    图中有效地址经过变换后,十进制物理地址 a 应为( )。

    A、33220
    B、8644
    C、4548
    D、2500

    查看答案

    试题参考答案:A

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/15

  • 试题10

    某财务系统的一个组件中,某个变量没有正确初始化,( ),最可能发现该错误。
    A.单元测试

    查看答案

    试题参考答案:A

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/10/15

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