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软件设计师每日一练试题(2026/8/17)

2026年08月18日来源:信管网 作者:cnitpm

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软件设计师每日一练试题内容(2026/8/17)

  • 试题1

    软件项目成本估算模型COCOM01I中,体系结构阶段模型基于(  )进行估算。
    A.应用程序点数量

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    试题参考答案:D

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/8/17

  • 试题2

    若循环队列以数组 Q[O..m-1] 作为其存储结构叭变量 rear 表示循环队列中队尾元素的实际位置,其移动按 rear=(rear+1) mod m 进行,变量 length 表示当前循环队列中的元素个数,则循环队列的队首元素的实际位置是( )。
    A、rear-length 
    B、(rear-length+m) mod m 
    C、(1+rear+m-length) mod m 
    D、m-length 

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    试题参考答案:C

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/8/17

  • 试题3

    The project workbook is not so much a separate document as it is a structure imposed on the documents that the project will be producing anyway.
    All the documents of the project need to be part of this ( ). This includes objectives ,external specifications , interface specifications , technical standards , internal specifications and administrative memoranda(备忘录).
    Technical prose is almost immortal. If one examines the genealogy ( Ff ) of a customer manual for a piece of hardware or software , one can trace not only the ideas , but also many of the very sentences and paragraphs back to the first (请作答此空) proposing the product or explaining the first design. For the technical writer, the paste-pot is as mighty as the pen.
    Since this is so, and since tomorrow's product-quality manuals will grow from today’s memos, it is very important to get the structure of the documentation right. The early design of the project ( ) ensures that the documentation structure itself is crafted, not haphazard. Moreover, the establishment of a structure molds later writing into segments that fit into that structure.
    The second reason for the project workbook is control of the distribution of ( ). The problem is not to restrict information, but to ensure that relevant information gets to all the people who need it.
    The first step is to number all memoranda, so that ordered lists of titles are available and h worker can see if he has what he wants. The organization of the workbook goes well beyond this to establish a tree-structure of memoranda. The ( ) allows distribution lists to be maintained by subtree, if that is desirable.
    A.objective

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    试题参考答案:B

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/8/17

  • 试题4

    数字证书是由 ( ) 颁发的。
    A.网上商店

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    试题参考答案:B

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/8/17

  • 试题5

    分治算法设计技术( )。
    A.一般由三个步骤组成:问题划分、递归求解、合并解

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    试题参考答案:A

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/8/17

  • 试题6

    某文件管理系统为了记录磁盘的使用情况,在磁盘上建立了位示图(bitmap)。若系统中字长为 16 位,磁盘上的物理块依次编号为:0、1、2、…,那么 8192 号物理块的使用情况在位示图中的第  ( )  个字中描述。
    A、256
    B、257
    C、512
    D、513

    查看答案

    试题参考答案:D

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/8/17

  • 试题7

    关系规范化在数据库设计的( )阶段进行。
    A.需求分析

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    试题参考答案:C

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/8/17

  • 试题8

    以下关于拒绝服务攻击的叙述中,不正确的是( )。
    A.拒绝服务攻击的目的是使计算机或者网络无法提供正常的服务

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    试题参考答案:C

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/8/17

  • 试题9

    设栈S和队列Q的初始状态均为空,元素abcdefg依次进入栈S,若每个元素出栈后立即进入队列Q,且7个元素出队的顺序是bdcfeag,则栈S的容量至少是( )。
    A.2

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    试题参考答案:B

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/8/17

  • 试题10

    800×600的分辨率的图像,若每个像素具有16位的颜色深度,则可表示 ( ) 种不同的颜色。
    A、1000
    B、1024
    C、65536
    D、480000

    查看答案

    试题参考答案:C

    完整试题与解析:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2026/8/17

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