试题1

（ ）  是指在运行时把过程调用和响应调用所需要执行的代码加以结合。
A、绑定
B、静态绑定
C、动态绑定
D、继承

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试题2

there is nothing in this world constant but inconstancy.-SWIFT
Project after project designs a set of algorithms and then plunges intoconstruction of customer-deliverable software on a schedule that demands delivery of the first thing built.
In most projects, the first system built is (1) usable. It may be too slow, too big , awkward to use, or all three. There is no (2 ) but to start again, smarting but smarter and build a redesigned version in which these problems are solved. The discard and (3) may be done in one lump, or it may be done piece-by-piece. But all large-system experience shows that it will be done. Where a new system concept or new technology is used, one has to build a syste m to throw away, for even the best
planning is not so omniscient (全知的) as to get it fight the first time.
the management question, therefore, is not whether to build a pilot system and throw it away. You will do that. The only question is whether to plan in advance to build a (4).or to promise to deliver the throwaway to customers. Seen this way, the answer is much clearer. Delivering that throwaway to customers buys time, but it does so only at the (5) of agony (极大痛苦) for the user, distraction for the builders while they do the redesign, and a bad..reputation for the product that the best redesign will find hard to live down.
Henceplanto throw one away; you will,anyhow.
The management question, therefore, is not whether to build a pilot system and throw it away. You will do that. The only question is whether to plan in advance to build a throwaway, or to promise to deliver the throwaway to customers. Seen this way, the answer is much clearer. Delivering that throwaway to customers buys time, but it does so only at the cost of agony for the user, distraction for the builders while they do the redesign, and a bad reputation for the product that the best redesign will find hard to live down.
(1)A.almost
B.often
C.usually
D.barely
(2)A.alternative
B.need
C.possibility
D.solution
(3)A.design
B.redesign
C.plan
D.build
(4) A.throwaway
B.system
C.software
D.product
(5) A.worth
B. value
C. cost
D. invaluable

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试题3

在屏蔽软件错误的容错系统中，冗余附加技术的构成不包括（）。
A．关键程序和数据的冗余存储及调用
B．冗余备份程序的存储及调用
C．实现错误检测和错误恢复的程序
D．实现容错软件所需的固化程序

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试题4

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试题5

因使用大量的对象而造成很大的存储开销时，适合采用（ ）模式进行对象共享，以减少对象数量从而达到较少的内存占用并提升性能。
A．组合（Composite）
B．享元（Flyweight）
C．迭代器（Iterator）
D．备忘（Memento）

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试题6

正常情况下，操作系统对保存有大量有用数据的硬盘进行  （ ）  操作时，不会清除有用数据。
A、磁盘分区和格式化
B、磁盘格式化和碎片整理
C、磁盘清理和碎片整理
D、磁盘分区和磁盘清理

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试题7

设循环队列 Q 的定义中有 rear 和 len 两个域变量，其中 rear 表示队尾元素的指针，len 表示队列的长度，如下图所示（队列长度为 3，队头元素为 e）。设队列的存储空间容量为 M，则队头元素的指针为（ ）  。

A、(Q.rear+Q.len-1)
B、(Q.rear+Q.len-1+M)%M
C、(Q.rear-Q.len+1)
D、(Q.rear-Q.len+1+M)%M

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试题8

面向对象分析与设计中的 （1）  是指一个模块在扩展性方面应该是开放的，而在更改性方面应该是封闭的；而 （2）  是指子类应当可以替换父类并出现在父类能够出现的任何地方。
（1）A、开闭原则
B、替换原则
C、依赖原则
D、单一职责原则
（2）A、开闭原则
B、替换原则
C、依赖原则
D、单一职责原则

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试题9

在如下所示的进程资源图中，( )。




A.P1、P2、P3都是非阻塞节点，该图可以化简，所以是非死锁的
B．P1、P2、P3都是阻塞节点，该图不可以化简，所以是死锁的
C．P1、P2是非阻塞节点，P3是阻塞节点，该图不可以化简，所以是死锁的
D．P2是阻塞节点，P1、P3是非阻塞节点，该图可以化简，所以是非死锁的

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试题10

若排序前后关键字相同的两个元素相对位置不变，则称该排序方法是稳定的。（ ）排序是稳定的。
A、归并
B、快速
C、希尔
D、堆

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