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软件设计师案例分析每日一练试题内容(2024/12/27)
阅读下列说明和C++代码,将应填入(n)处的字句写在答题纸的对应栏内。
【说明】
某咖啡店当卖咖啡时,可以根据顾客的要求在其中加入各种配料,咖啡店会根据所加入的配料来计算费用。咖啡店所供应的咖啡及配料的种类和价格如下表所示。
咖啡 | 价格/杯 | 配 料 | 价格/份 |
蒸馏咖啡(Espresso) | 25 | 摩卡(Mocha) | 10 |
深度烘焙咖啡(DarkRoast) | 20 | 奶泡(Whip) | 8 |
现采用装饰器(Decorator)模式来实现计算费用的功能,得到如图5-1所示的类图

【C++代码】
#include
#include
using namespace std;
const int ESPRESSO_PRICE = 25;
const int DRAKROAST_PRICE = 20;
const int MOCHA_PRICE = 10;
const int WHIP_PRICE = 8;
class Beverage { //饮料
(1) :string description;
public:
(2) ( ){ return description; }
(3) ;
};
class CondimentDecorator : public Beverage { //配料
protected:
(4) ;
};
class Espresso : public Beverage { //蒸馏咖啡
public:
Espresso ( ) {description="Espresso"; }
int cost ( ){return ESPRESSO_PRICE; }
};
class DarkRoast : public Beverage { //深度烘焙咖啡
public:
DarkRoast( ){ description = "DardRoast"; }
int cost( ){ return DRAKROAST_PRICE; }
};
class Mocha : public CondimentDecorator { //摩卡
public:
Mocha(Beverage*beverage){ this->beverage=beverage; }
string getDescription( ){ return beverage->getDescription( )+",Mocha"; }
int cost( ){ return MOCHA_PRICE+beverage->cost( ); }
};
class Whip :public CondimentDecorator { //奶泡
public:
Whip(Beverage*beverage) { this->beverage=beverage; }
string getDescription( ) {return beverage->getDescription( )+",Whip"; }
int cost( ) { return WHIP_PRICE+beverage->cost( ); }
};
int main() {
Beverage* beverage = new DarkRoast( );
beverage=new Mocha( (5) );
beverage=new Whip( (6) );
cout
return 0;
}
编译运行上述程序,其输出结果为:
DarkRoast, Mocha, Whip ¥38
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信管网考友试题答案分享:
信管网cnit**************:
1 privater
2 string getdescription
3 int cost()
4 beverage beverage
5 beverage
6 beverage
信管网cnit*********:
1、public
2、beverage
3、public : int cost;
5、""
6、
信管网试题答案与解析:www.cnitpm.com/exam/ExamDayAL.aspx?t1=4&day=2024/12/27