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软件设计师每日一练试题(2024/11/11)

2024年11月12日来源:信管网 作者:cnitpm

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软件设计师每日一练试题内容(2024/11/11)

  • 试题1

    Thebeautyofsoftwareisinitsfunction,initsinternalstructure,andinthewayinwhichitiscreatedbyateam.Toauser,aprogramwithjusttherightfeaturespresentedthroughanintuitiveand()interfaceisbeautiful.Toasoftwaredesigner,aninternalstructurethatispartitionedinasimpleandintuitivemanner,andthatminimizesinternalcouplingisbeautiful.Todevelopersandmanagers,amotivatedteamofdevelopersmakingsignificantprogresseveryweek,andproducingdefect-freecode,isbeautiful.Thereisbeautyonalltheselevels.
    ourworldneedssoftware--lotsofsoftware.Fiftyyearsagosoftwarewassomethingthatraninafewbigandexpensivemachines.Thirtyyearsagoitwassomethingthatraninmostcompaniesandindustrialsettings.Nowthereissoftwarerunninginourcellphones,watches,appliances,automobiles,toys,andtools.Andneedfornewandbettersoftwarenever().Asourcivilizationgrowsandexpands,asdevelopingnationsbuildtheirinfrastructures,asdevelopednationsstrivetoachieveevergreaterefficiencies,theneedformoreandmoreSoftware()toincrease.Itwouldbeagreatshameif,inallthatsoftware,therewasnobeauty.
    Weknowthatsoftwarecanbeugly.Weknowthatitcanbehardtouse,unreliable,andcarelesslystructured.Weknowthattherearesoftwaresystemswhosetangledandcarelessinternalstructuresmakethemexpensiveanddifficulttochange.Weknowthattherearesoftwaresystemsthatpresenttheirfeaturesthroughanawkwardandcumbersomeinterface.Weknowthattherearesoftwaresystemsthatcrashandmisbehave.Theseare()systems.Unfortunately,asaprofession,softwaredeveloperstendtocreatemoreuglysystemsthanbeautifulones.

    Thereisasecretthatthebestsoftwaredevelopersknow.Beautyischeaperthanugliness.Beautyisfasterthanugliness.Abeautifulsoftwaresystemcanbebuiltandmaintainedinlesstime,andforlessmoney,thananuglyone.Novicesoftwaredevelopersdon't.understandthis.Theythinkthattheyhavetodoeverythingfastandquick.Theythinkthatbeautyis().No!Bydoingthingsfastandquick,theymakemessesthatmakethesoftwarestiff,andhardtounderstand,Beautifulsystemseflexibleandeasytounderstand.Buildingthemandmaintainingthemisajoy.Itisuglinessthatisimpractical.Uglinesswillslowyoudownandmakeyoursoftwareexpensiveandbrittle.Beautifulsystemscosttheleastbuildandmaintain,andaredeliveredsoonest.
    A.Simple
    B.Hard
    C.Complex
    D.Duplicated
    A.happens
    B.exists
    C.stops
    D.starts
    A.starts
    B.continues
    C.appears
    D.stops
    A.practical
    B.useful
    C.beautiful
    D.ugly
    A.impractical
    B.perfect
    C.time-wasting
    D.practical

    查看答案

    试题参考答案:A、C、B、D、A

    试题解析与讨论:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2024/11/11

  • 试题2

    数据流图中某个加工的一组动作依赖于多个逻辑条件的取值,则用( )能够清楚地表示复杂的条件组合与应做的动作之间的对应关系。
    A.流程图
    B.NS盒图
    C.形式语言
    D.决策树

    查看答案

    试题参考答案:D

    试题解析与讨论:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2024/11/11

  • 试题3

    在某销售系统中,客户采用扫描二维码进行支付。若采用面向对象方法开发该销售系统,则客户类属于(1)类, 二维码类属于( 2)类。
    (1)A.接口
    B.实体
    C.控制
    D.状态
    (2)A.接口
    B.实体
    C.控制
    D.状态

    查看答案

    试题参考答案:B、A

    试题解析与讨论:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2024/11/11

  • 试题4

    在Windows 2003 Server中启用配置SNMP服务时,必须以()身份登录才能完成SNMP服务的配置功能。
    A.guest
    B.普通用户
    C.administrator组成员
    D.user组成员

    查看答案

    试题参考答案:C

    试题解析与讨论:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2024/11/11

  • 试题5

    已知某二叉树的先序遍历序列为A B C D E F、中序遍历序列为B A D C F E,则可以确定该二叉树( )。
    A.是单支树(即非叶子结点都只有一个孩子)
    B.高度为4(即结点分布在4层上)
    C.根结点的左子树为空
    D.根结点的右子树为空

    查看答案

    试题参考答案:B

    试题解析与讨论:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2024/11/11

  • 试题6

    将网址转换为IP地址要用()协议。
    A.域名解析
    B.IP地址解析
    C.路由选择
    D.传输控制

    查看答案

    试题参考答案:A

    试题解析与讨论:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2024/11/11

  • 试题7

    软件的复杂性主要体现在程序的复杂性。(1)是度量软件复杂性的一个主要参数。若采用McCabe度量法计算环路复杂性,则对于下图所示的程序图,其环路复杂度为(2)。



    30、A.代码行数
    B.常量的数量
    C.变量的数量
    D.调用的库函数的数量
    31、A.2
    B.3
    C.4
    D.5

    查看答案

    试题参考答案:A、C

    试题解析与讨论:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2024/11/11

  • 试题8

    The project workbook is not so much a separate document as it is a structure imposed on the documents that the project will be producing anyway.
    All the documents of the project need to be part of this ( ). This includes objectives ,external specifications , interface specifications , technical standards , internal specifications and administrative memoranda(备忘录).
    Technical prose is almost immortal. If one examines the genealogy ( Ff ) of a customer manual for a piece of hardware or software , one can trace not only the ideas , but also many of the very sentences and paragraphs back to the first ( ) proposing the product or explaining the first design. For the technical writer, the paste-pot is as mighty as the pen.
    Since this is so, and since tomorrow's product-quality manuals will grow from today’s memos, it is very important to get the structure of the documentation right. The early design of the project ( ) ensures that the documentation structure itself is crafted, not haphazard. Moreover, the establishment of a structure molds later writing into segments that fit into that structure.
    The second reason for the project workbook is control of the distribution of (请作答此空). The problem is not to restrict information, but to ensure that relevant information gets to all the people who need it.
    The first step is to number all memoranda, so that ordered lists of titles are available and h worker can see if he has what he wants. The organization of the workbook goes well beyond this to establish a tree-structure of memoranda. The ( ) allows distribution lists to be maintained by subtree, if that is desirable.
    A.product
    B.manual
    C.document
    D.information

    查看答案

    试题参考答案:D

    试题解析与讨论:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2024/11/11

  • 试题9

    在如下所示的进程资源图中,(1);该进程资源图是(2)。

    (1)A.P1、P2、P3都是阻塞节点
    B.P1是阻塞节点、P2、P3是非阻塞节点
    C.P1、P2是阻塞节点、P3是非阻塞节点
    D.P1、P2是非阻塞节点、P3是阻塞节点
    (2)A.可以化简的,其化简顺序为P1→P2→P3
    B.可以化简的,其化简顺序为P3→P1→P2
    C.可以化简的,其化简顺序为P2→P1→P3
    D.不可以化简的,因为P1、P2、P3申请的资源都不能得到满足

    查看答案

    试题参考答案:C、B

    试题解析与讨论:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2024/11/11

  • 试题10

    下面的 UML 类图描绘的是  (1) 设计模式。关于该设计模式的叙述中,错误的是  (2) 。

    (1)A、桥接
    B、策略
    C、抽象工厂
    D、观察者
    (2)A、该设计模式中的 Observer 需要维护至少一个 Subject 对象
    B、该设计模式中的 ConcreteObserver 可以绕过 Subject 及其子类的封装
    C、该设计模式中一个 Subject 对象需要维护多个 Observer 对象
    D、该设计模式中 Subject 需要通知 Observer 对象其自身的状态变化

    查看答案

    试题参考答案:D、B

    试题解析与讨论:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2024/11/11

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