信管网每日一练
软件设计师 - 每日一练 导航

软件设计师案例分析每日一练试题(2024/4/13)

2024年04月14日来源:信管网 作者:cnitpm

软件设计师案例分析当天每日一练试题地址:www.cnitpm.com/exam/ExamDayAL.aspx?t1=4

往期软件设计师每日一练试题汇总:www.cnitpm.com/class/27/e4_1.html

软件设计师案例分析每日一练试题(2024/4/13)在线测试:www.cnitpm.com/exam/ExamDayAL.aspx?t1=4&day=2024/4/13

点击查看:更多软件设计师习题与指导

软件设计师案例分析每日一练试题内容(2024/4/13)

试题六
阅读以下说明和C++代码。
【说明】
传输门是传输系统中的重要装置。传输门具有Open(打开)、Closed(关闭)、Opening (正在打开)、StayOpen(保持打开)和Closing(正在关闭)五种状态。触发传输门状态转换的事件有click、complete和timeout三种。事件与其相应的状态转换如下图所示。

下面的C++代码1与C++代码2分别用两种不同的设计思路对传输门进行状态模拟,请填补代码中的空缺。
【C++代码1】
const int CLOSED=1;   const int OPENING=2;
const int OPEN=3;     const int CLOSING=4;
const int STAYOPEN=5;  //定义状态变量,用不同整数表示不同状态
class Door {
Private:
int state;  //传输门当前状态
void setState(int state){ this->state=state;}  //设置当前状态
public:
Door():state(CLOSED.{};
void getState(){    //根据当前状态输出相应的字符串
switch(state){
case OPENING: cout<<"OPENING"<<endl;    break;
case CLOSED:  cout<<"CLOSED"<<endl;     break;
case OPEN:    cout<<"OPEN"<<endl;       break;
case CLOSING: cout<<"CLOSING"<<endl;    break;
case STAYOPEN:cout<<"STAYOPEN"<<endl;   break;
}
};
void click()  {    //发生click事件时进行状态转换
if (  (1)  )    setState(OPENING.;
else if (  (2)  )    setState(CLOSING.;
else if (  (3)  )    setState(STAYOPEN);
}
void timeout(){    //发生timeout事件时进行状态转换
if (state == OPEN)  setState(CLOSING.;
}
void complete(){    //发生complete事件时进行状态转换
if (state == OPENING.    setState(OPEN);
else if (state == CLOSING.  setState(CLOSED.;
}
};
int main(){
Door aDoor;
aDoor.getState();aDoor.click();    aDoor.getState();
aDoor.complete();aDoor.getState(); aDoor.click();
aDoor.getState();aDoor.click();    aDoor.getState();    return 0;
}
【C++代码2】
class Door {
public:
DoorState *CLOSED,*OPENING,*OPEN,*CLOSING,*STAYOPEN,*state;
Door();
virtual~Door(){……//释放申请的内存,此处代码省略);
void setState(DoorState *state)  { this->state = state;}
void getState(){
//此处代码省略,本方法输出状态字符串,
//例如,当前状态为CLOSED时,输出字符串为“CLOSED”
};
void click();
void timeout();
void complete();
};
Door::Door(){
CLOSED = new DoorClosed(this);    OPENING = new DoorOpening(this);
OPEN = new DoorOpen(this);        CLOSING = new DoorClosing(this);
STAYOPEN = new DoorStayOpen(this);state = CLOSED;
}
void Door :: click() {  (4)  ;)
void Door :: timeout() {  (5)  ;)
void Door :: complete() {  (6)  ;}
class DoorState//定义一个抽象的状态,它是所有状态类的基类
{
protected:Door *door;
public:
DoorState(Door *door) {this->door = door;}
virtual~DoorState(void);
virtual void click()  {}
virtual void complete()  {}
virtual void timeout()  {}
};
class DoorClosed :public DoorState{//定义一个基本的Closed状态
public:
DoorClosed(Door *door) :DoorState(door)  {}
virtual ~ DoorClosed(){}
void click();
};
void DoorClosed :: click() {  (7)  ;}
//其他状态类的定义与实现代码省略
int main() {
Door aDoor;
aDoor.getState();aDoor.click();aDoor.getState();aDoor.complete();
aDoor.getState();aDoor.timeout();aDoor.getState();return 0;
}



信管网试题答案与解析:www.cnitpm.com/st/245488533.html

信管网考友试题答案分享:

信管网cnitpm488202624972:
1.state == closed || state == closing 2.state == opening || state == stayopen 3.state == open

信管网cnitpm475547856609:
state==closed state==stayopen‖state==opening state==open state->click() state->timeout() state->complete()

信管网试题答案与解析:www.cnitpm.com/st/245488533.html

温馨提示:因考试政策、内容不断变化与调整,信管网提供的以上信息仅供参考,如有异议,请考生以权威部门公布的内容为准!

分享至:

信管网 - 信息系统项目管理专业网站

下载APP-在线学习

培训课程

0元畅享

考试题库

免费资料

客服咨询