2023年12月11日来源:信管网 作者:cnitpm
软件设计师当天每日一练试题地址:www.cnitpm.com/exam/ExamDay.aspx?t1=4
往期软件设计师每日一练试题汇总:www.cnitpm.com/class/27/e4_1.html
软件设计师每日一练试题(2023/12/10)在线测试:www.cnitpm.com/exam/ExamDay.aspx?t1=4&day=2023/12/10
点击查看:更多软件设计师习题与指导
软件设计师每日一练试题内容(2023/12/10)
试题1
计算机中CPU的中断响应时间指的是( )的时间
A.从发出中断请求到中断处理结束
B.从中断处理开始到中断处理结束
C.CPU分析判断中断请求
D.从发出中断请求到开始进入中断处理程序
查看答案
试题参考答案:D
试题解析与讨论:www.cnitpm.com/st/254074351.html
试题2
王某是某公司的软件设计师,每当软件开发完成后均按公司规定编写软件文档,并提交公司存档。那么该软件文档的著作权( )享有。
A. 应由公司
B. 应由公司和王某共有
C. 应由王某
D. 除署名权外,著作权的其它权利由王某
查看答案
试题参考答案:A
试题3
下面关于校验方法的叙述, ( ) 是正确的。
A、采用奇偶校验可检测数据传输过程中出现一位数据错误的位置并加以纠正
B、采用海明校验可检测数据传输过程中出现一位数据错误的位置并加以纠正
C、采用海明校验,校验码的长度和位置可随机设定
D、采用 CRC 校验,需要将校验码分散开并插入数据的指定位置中
查看答案
试题参考答案:B
试题解析与讨论:www.cnitpm.com/st/80962788.html
试题4
某程序的程序图如下图所示,运用 McCabe 度量法对其进行度量,其环路复杂度是 ( ) 。
A、4
B、5
C、6
D、8
查看答案
试题参考答案:C
试题解析与讨论:www.cnitpm.com/st/82922855.html
试题5
一棵满二叉树,其每一层结点个数都达到最大值,对其中的结点从1开始顺序编号,即根结点编号为1,其左、右孩子结点编号分别为2和3,再下一层从左到右的编号为4、5、6、7,依此类推,每一层都从左到右依次编号,直到最后的叶子结点层为止,则用()可判定编号为m和n的两个结点是否在同一层。
A.log2m=log2n
B.[log2m]=[=[log2n]
C.[log2m]+1=[log2n]
D.[log2m]=[log2n]+1
查看答案
试题参考答案:B
试题解析与讨论:www.cnitpm.com/st/247185724.html
试题6
如下所示的 UML 状态图中,( )时,不一定会离开状态 B。
A.状态 B 中的两个结束状态均达到
B.在当前状态为 B2 时,事件 e2 发生
C.事件 e2 发生
D.事件 el 发生
查看答案
试题参考答案:C
试题7
自底向上的集成测试策略的优点包括( )。
A.主要的设计问题可以在测试早期处理
B.不需要写驱动程序
C.不需要写桩程序
D.不需要进行回归测试
查看答案
试题参考答案:C
试题解析与讨论:www.cnitpm.com/st/254854615.html
试题8
对于大多数通用程序设计语言,用()描述其语法即可。
A.正规文法
B.上下文无关文法
C.上下文有关文法
D.短语结构文法
查看答案
试题参考答案:B
试题9
Software entities are more complex for their size than perhaps any other humanconstruct, because no two parts are alike (at least above the statement level). If they are, wemake the two similar parts into one, a( 71 ), open or closeD. In this respect software systemsdiffer profoundly from computers, buildings, or automobiles, where repeated elements abound.
Digital computers . are themselves more complex than most things people build;they have very large numbers of states This makes conceiving, describing, and testing them harD. Software systems have orders of magnitude more( 72 )than computers do
Likewise, a scaling-up of a software entity is not m erely a repetition of the same elementsm larger size; it is necessarily an mcrease in the number of different elements. In most cases, the elements interact with each other in some( 73 )fashion: and the complexity of the wholencreases much more than linearly.
The complexity of software is a(an)( 74 )property, not an accidental one Hencedescriptions of a software entity that abstract away its complexity often abstract away its essence.Mathematics and the physical sciences made great strides for threecenturies by constructingsimplified models of complex phenomena, deriving properties fiom the models, and verifyingthose properties experimentally. This worked becausethe complexities( 75 ) in the modelswere not the .essential properties of the phenomena: It does not work when the complexities are the essence.
Many of the classical problems of developing software products derive from this essential complexi and its nonlinear uicreases with size. Not only .technical problems but management problems as well come from the coin plexity.
A. task
B.job
C.subroitune
D.Program
A.states
B.parts
C.conditions
D.Expressions
A.linear
B. nonlinear
C.Parallel
D.Addititive
A. surface
B. Outside
C.exterior
D.Essential
A. fixed
B. Included
C.ignored
D.stabilized
查看答案
试题参考答案:C、A、B、D、C
试题10
循环冗余校验码(CRC.利用生成多项式进行编码。设数据位为k位,校验位为r位,则CRC码的格式为()。
A.k个数据位之后跟r个校验位
B.r个校验位之后跟k个数据位
C.r个校验位随机加入k个数据位中
D.r个校验位等间隔地加入k个数据位中
查看答案
试题参考答案:A
试题解析与讨论:www.cnitpm.com/st/247971666.html
温馨提示:因考试政策、内容不断变化与调整,信管网提供的以上信息仅供参考,如有异议,请考生以权威部门公布的内容为准!
相关推荐